AMC 10B/12B 2024 (Problem 2/2)What is 10!−7!⋅6!10!-7!\cdot6!10!−7!⋅6!?(A) −120\text{(A)}\;-120(A)−120(B) 0\text{(B)}\;0(B)0(C) 120\text{(C)}\;120(C)120(D) 600\text{(D)}\;600(D)600(E) 720\text{(E)}\;720(E)720Check AnswerYour answer:ABCDECheckHints (2)Hint 1Factorize.Hint 210!−7!⋅6!=7!(8⋅9⋅10−6⋅5⋅4⋅3⋅2)10!-7!\cdot6!=7!(8\cdot9\cdot10-6\cdot5\cdot4\cdot3\cdot2)10!−7!⋅6!=7!(8⋅9⋅10−6⋅5⋅4⋅3⋅2)=7!(720−720)=0=7!(720-720)=0=7!(720−720)=0Final Answer(B) 000