Apply the Pythagorean Theorem to triangles ACD and BCD. AC2=AD2+CD2BC2=BD2+CD2
Subtract the two equations. AD2−BD2=AC2−BC2=752−452.
Find BD.
Using Toolkit 10 — Difference of squares, (AD−BD)(AD+BD)=752−452. Since AD+BD=AB=80, we obtain (AD−BD)⋅80=(75−45)(75+45)=30⋅120. Hence AD−BD=45. Solve the system AD+BD=80,AD−BD=45, to obtain BD=235.
Find CD.
Using the Pythagorean Theorem, CD2=BC2−(235)2, so CD=22511.