Square ABCD has sides of length 4. Points P and Q lie on AD and CD, respectively, with AP=58 and DQ=310. A path begins along the segment from P to Q and continues by reflecting against the sides of ABCD (with congruent incoming and outgoing angles). If the path hits a vertex of the square, it terminates there; otherwise it continues forever. At which vertex does the path terminate?
Instead of reflecting the path inside the square, we can reflect the square and extend the path. The intersections of both paths are similar. (CL1=CL)