AMC 10B 2025 (Problem 3)

A Pascal-like triangle has 1010 as the top row and 1010 followed by 11 as the second row. In each subsequent row the first number is 1010, the last number is 11, and, as in the standard Pascal's Triangle, each other number in the row is the sum of the two numbers directly above it. The first four rows are shown below:10101101111021121\begin{array}{ccccccc}&&&10&&&\\ &&10&&1&&\\ &10&&11&&1&\\ 10&&21&&12&&1\end{array}
What is the sum of the digits of the sum of the numbers in the
1111th row?
(A)  11\text{(A)}\;11(B)  13\text{(B)}\;13(C)  14\text{(C)}\;14(D)  16\text{(D)}\;16(E)  17\text{(E)}\;17