Section Formula

Lesson · Beginner

Geometry: Coordinate Geometry

Point C dividing segment AB in the ratio m to n
ACCB=mn\frac{AC}{CB}=\frac{m}{n}
C=mB+nAm+nC=\frac{mB+nA}{m+n}

If

A=(x1,y1),B=(x2,y2)A=(x_1,y_1),\qquad B=(x_2,y_2)

then

C=(nx1+mx2m+n,ny1+my2m+n)C=\left(\frac{nx_1+mx_2}{m+n},\frac{ny_1+my_2}{m+n}\right)