Square-Root Long-Division Algorithm

Lesson · Beginner

Algebra

Step 1 — Separate the Digits into Pairs

Starting from the right, separate the digits into pairs, moving from right to left.

At the left end, one or two digits will remain.

Grouping the digits of 4047 as 40 and 47, and 954 as 9 and 54, using the square-root long-division layout.

Step 2 — Find the First Digit

Look at the leftmost group.

Find the largest digit whose square is less than or equal to that group.

62≤40<726^2\le40<7^2
32≤9<423^2\le9<4^2
The first square-root digits are 6 for 4047 and 3 for 954.

Step 3 — Square and Subtract

Square the digit you just wrote and subtract its square from the leftmost group. Then bring down the next pair of digits and place it to the right of the remainder.

Subtracting 36 from 40 and bringing down 47 to obtain 447; subtracting 9 from 9 and bringing down 54 to obtain 54.

Step 4 — Find the Next Digit

Multiply the part of the square root found so far by 2.

Then append an empty digit position to the result and multiply by the digit placed in that position:

12◯×◯12\bigcirc\times\bigcirc

The same digit must be placed in both circles.

Choose the largest digit from 0 to 9 such that the resulting product is less than or equal to the current number.

Testing digits 0 through 4 in 12x times x for 447, and digits 0 and 1 in 6x times x for 54. The chosen digits are 3 and 0.

Step 5 — Multiply and Subtract

Move the chosen digit into the next position of the square root. Then multiply and subtract the product from the current number.

Completing the integer parts of the square roots: 4047 gives 63 with remainder 78, and 954 gives 30 with remainder 54.

Therefore,

4047=63.  …\sqrt{4047}=63.\;\ldots
954=30.  …\sqrt{954}=30.\;\ldots