AIME II 2025 (Problem 4)

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The product ∏k=463log⁡k(5k2−1)log⁡k+1(5k2−4)\displaystyle \prod_{k=4}^{63}\frac{\log_k(5^{k^2-1})}{\log_{k+1}(5^{k^2-4})} is equal to mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.