Toolkit 10Difference of squaresa2−b2=(a−b)(a+b)a^2-b^2=(a-b)(a+b)a2−b2=(a−b)(a+b)ProofUsing the distributive law,(a−b)(a+b)=a2+ab−ab−b2=a2−b2.□\begin{aligned} (a-b)(a+b) &= a^2 + ab - ab - b^2 \\ &= a^2 - b^2. \quad\square \end{aligned}(a−b)(a+b)=a2+ab−ab−b2=a2−b2.□Related ProblemsCoreAMC 10A 2024 (Problem 11)AMC 10A/12A Spring 2021 (Problem 10/9)AMC 10A 2012 (Problem 22)AMC 10B 2023 (Problem 14)BMO1 2016/2017 (Problem 3)AMC 10A/12A 2024 (Problem 15/9)AMC 10A 2023 (Problem 23)MajorAMC 12B 2025 (Problem 3)MinorAIME II 2022 (Problem 10)AMC 10A/12A 2025 (Problem 23/16)AIME II 2025 (Problem 4)MathCounts 2026 Chapter Sprint Round (Problem 30)AMC 10A/12A 2022 (Problems 23/20)MATHCOUNTS State Sprint 2025 (Problem 26)AMC 12A 2025 (Problem 21)