AMC 12A 2025 (Problem 14)

Points FF, GG, and HH are collinear with GG between FF and HH. The ellipse with foci at GG and HH is internally tangent to the ellipse with foci at FF and GG, as shown below. The two ellipses have the same eccentricity ee, and the ratio of their areas is 20252025. (Recall that the eccentricity of an ellipse is e=cae=\frac{c}{a}, where cc is the distance from the center to a focus, and 2a2a is the length of the major axis.) What is ee?
Two internally tangent ellipses with collinear foci F, G, and H
(A)  35\text{(A)}\;\frac{3}{5}(B)  1625\text{(B)}\;\frac{16}{25}(C)  45\text{(C)}\;\frac{4}{5}(D)  2223\text{(D)}\;\frac{22}{23}(E)  4445\text{(E)}\;\frac{44}{45}