AIME I 2026 (Problem 3)

A hemisphere with radius 200 sits on top of a horizontal circular disk with radius 200, and the hemisphere and disk have the same center. Let TT be the region of points PP in the disk such that a sphere of radius 42 can be placed on top of the disk at PP and lie completely inside the hemisphere. The area of TT divided by the area of the disk is pq\frac{p}{q}, where pp and qq are relatively prime positive integers. Find p+qp+q.