Nonnegative Squares

Idea · Beginner

Algebra

For every real number xx,

x2≥0,x^2\ge 0,

with equality if and only if

x=0.x=0.

Therefore, whenever an expression can be written as a sum of squares

A12+A22+⋯+An2,A_1^2+A_2^2+\cdots+A_n^2,

we immediately know

A12+A22+⋯+An2≥0.A_1^2+A_2^2+\cdots+A_n^2\ge 0.

Moreover,

A12+A22+⋯+An2=0A_1^2+A_2^2+\cdots+A_n^2=0

if and only if

A1=A2=⋯=An=0.A_1=A_2=\cdots=A_n=0.

This gives a powerful strategy:

Rewrite the desired inequality as a sum of nonnegative squares.


For example,

a2+b2≥2aba^2+b^2\ge 2ab

because

a2+b2−2ab=(a−b)2≥0.a^2+b^2-2ab=(a-b)^2\ge 0.

Equality occurs exactly when

a=b.a=b.

Completing the Square

x2−6x+13=(x−3)2+4.x^2-6x+13=(x-3)^2+4.

Hence

x2−6x+13≥4.x^2-6x+13\ge 4.