Toolkit 6Square of a sum(a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2(a+b)2=a2+2ab+b2ProofUsing the distributive law,(a+b)2=(a+b)(a+b)=a2+ab+ba+b2=a2+2ab+b2.□\begin{aligned} (a+b)^2 &= (a+b)(a+b) \\ &= a^2 + ab + ba + b^2 \\ &= a^2 + 2ab + b^2. \quad\square \end{aligned}(a+b)2=(a+b)(a+b)=a2+ab+ba+b2=a2+2ab+b2.□Related ProblemsCoreAMC 10A 2020 (Problem 14)AMC 10B Spring 2021 (Problem 15)AMC 10B 2025 (Problem 7)MajorAMC 10A 2012 (Problem 22)AMC 10B 2023 (Problem 14)BMO1 2016/2017 (Problem 3)AMC 12B 2025 (Problem 8)MinorMathCounts 2026 Chapter Sprint Round (Problem 30)AMC 10A 2023 (Problem 23)AMC 10A/12A 2023 (Problem 18/22)